Question

the mass of ax2+bx+c=0 are both positive and b< 0. then​

Answer 1

Let r and s be the roots of equation then we know r+s=a−b and as L.H.S. is negative R.H.S. will also be negative.

As b<0,a has to be negative.

Now r∗s=ac and as L.H.S. is positive R.H.S. also has to be positive.

Thus a and c are of same sign and are negative.

Hence a<0,c<0

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