Question

the mass of bucket full of water is 15 kg . It is being pulled up from a 15 m deep well .due to hole in the bucket 6 kg water flow out of the bucket the work done in drawing the bucket out of the well is




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Answer 1

Explanation:

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Answer 2

Explanation:

ANSWER

Given, mass=15kg,h=15m ,mass escaped=6kg

Let's first find out the rate (say R) at which mass of bucket ( filled with water ) changes as it is lifted up ( due to leakage ) with respect to height ( to which it has been pulled ):

Total Change in Mass =6Kg

Total height it being pulled up =15m

Then;

R=6/15 Kg/m.

Assume it be constant throughout the process !!

Further ;

Let's suppose the bucket is lifted by a very small height (ds)

Then ;

Mass of bucket at that instant =15−[ 6/15×ds]

Then work done is given by :

(using W=mgh ) ⇒dW=15−[c×ds]×g×s

On integrating the above equation we get:

W=[15×g×s]- On integrating the above equation we get :

W=[15×g×s]−[ 6/15×(s^2/2)×g]

Now s ranges from 0 to 15m & taking g=10m/s^2

. using it in above equation we get,

W=(15×10×15)−[ 6/15×{(15)^2/2}×10 ]

On solving we get The Work done in the whole process which is

W=1800J