The mass of caco3 required to completely react with 25ml of 0.75M hcl
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Answer : 0.94g
Step-by-step explanation:
The 1000mL of HCl=27.375g then the 1ml of solution contains HCLl 27.375
1000×1
25ml of solution which contains HCl = 27.375 = 0.684g
1000×25
The chemical equation can be given as :
CaCO + 2HCl ------> CaCl + CO + H O
3(s) 2 2 2
2 mol of HCl reacts with 1 mol of CaCO
3
The amount of CaCO related is given by,
3
100 X 0.684g = 0.9639g ~ 0.94g
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