Question

the mass of CACO3 required to react completely with 20 mL of 1.0 M HCL as per the reaction , CACO3+2HCL=CACL2+CO2+H2O.....

Answer 1

1 mole of CaCO3 reacts with 2 moles of HCl from the equation.

We have 1M 20 mL HCl i.e. no of moles of HCl is : 20/1000 = 0.02

Thus no of moles required to completely consume 0.02 moles of HCl = 0.02/2 = 0.01

Mass of CaCO3 = no of moles * molar mass = 0.01*100 = 1g

Answer 2

Option a) 1 g is your answer