the mass of CaCO3 required to react completely with 20mL of 1.0M CHm as per the reaction CaCO3+2HCl gives CaCl2+CO2+H2O is
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Equation for the reaction :
CaCO₃ (s) + 2HCl (aq) — > CaCl₂ (s) + CO₂(g) + H₂O (l)
The mole ratio of Calcium Carbonate to Hydrochloric acid is 1 : 2.
Moles of HCl in 20ml of 1 M HCl.
20/1000 × 1 = 0.02 moles
Since the mole ratio is 1 : 2 the moles of Calcium carbonate will be :
0.02/2 = 0.01 moles
Molar mass of calcium carbonate = 100g/mol
Mass of Calcium Carbonate = molar mass of Calcium carbonate × moles of Calcium carbonate
= 100 × 0.01 = 1 gram
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