Question

The mass of cane sugar (C12 H,20,1) required for making 2L solution of 2M concentration is
3) 720g
1) 3428
4) 13689
2) 1080g

Answer 1

Answer:

Idk how to get the answer, but the answer is 1368 gram, hope it helps

Answer 2

Given,

volume of solvent = 2 liters

concentration of solution = 2 M

molecular weight of solute, cane sugar (C₁₂H₂₂O₁₁) = 342 g

To find,

Weight of solute used in making solution with 2M concentration

Solution,

Molarity is defined as the number of solute moles in per liter of the solvent. It is used to measure concentration of the solution.

The formula to calculate Molarity is

$M = \frac{n}{V}$

However number of solute moles can be given as,

$n = \frac{weight of solute}{molecular weight of solute}$

Therefore the formula for Molarity can be written as,

$M = \frac{weight of solute}{molecular weight of solute}$ × $\frac{1}{volume of solvent}$

$2 = \frac{weight of solute}{342}$ × $\frac{1}{2}$

weight of solute = 2 × 342 × 2

∴ weight of solute = 1368 g

Therefore the mass of cane sugar required to make 2 liter solution of 2M concentration is 1368 g.