The mass of cao that shall be obtained by heating 20kg of 90% pure limestone caco3 is
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Rxn involved -
CaCO3 → CaO + CO2
due to 90% purity, mass of CaCO3 available is 20× 0.9 = 18gm
so no. of moles of CaCO3 = 18/100 = 0.18
and 1 mole of CaCO3 yields 1 mole of CaO
therefore, mass of CaO produced = 0.18 × 56 = 10.08 gm
hope this helps
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