Chemistry, asked by magaldeep7270, 1 year ago

The mass of carbon content present in .75 mol of k4fecn6 is

Answers

Answered by vishal21431
2
1.what is the mass of carbon present in 0.5 mole of k4[Fe(CN)6],i.e., potassium ferracyanide?

2.calculate the no. of electrons present in 1.4gms of notrogen gas. 3. How many atoms and molecules of phosphorus r present in 124gms of phosphorus (P4)? 4.... show more

2 answers · Chemistry 

 Best Answer

1. There is 72g (6*12) of carbon in one mole hence 36g is carbon 

2. one mole of electrons has 6.022*10^23 electrons 
multiply by 14 since N2 has 14 electrons: 8.43*10^24 electrons per mole N2 
there are 0.05 moles of N2 = 

4.22*10^23 molecules of electrons 

3. 124/ 31 = 4 phosphorous atoms in 124g, this means there are 2.41*10^24 atoms 

4. pV=mRT/Mr => 202650*350*10^-6 = 1*8.31*273/Mr 

=> 70.9 = 2268.63/Mr 

Mr = 32.0 

your gas has Ar of 16 so your gas is Oxygen 

(no idea what you mean by 1gm of the gas)

Similar questions