The mass of carbon content present in .75 mol of k4fecn6 is
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1.what is the mass of carbon present in 0.5 mole of k4[Fe(CN)6],i.e., potassium ferracyanide?
2.calculate the no. of electrons present in 1.4gms of notrogen gas. 3. How many atoms and molecules of phosphorus r present in 124gms of phosphorus (P4)? 4.... show more
2 answers · Chemistry
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1. There is 72g (6*12) of carbon in one mole hence 36g is carbon
2. one mole of electrons has 6.022*10^23 electrons
multiply by 14 since N2 has 14 electrons: 8.43*10^24 electrons per mole N2
there are 0.05 moles of N2 =
4.22*10^23 molecules of electrons
3. 124/ 31 = 4 phosphorous atoms in 124g, this means there are 2.41*10^24 atoms
4. pV=mRT/Mr => 202650*350*10^-6 = 1*8.31*273/Mr
=> 70.9 = 2268.63/Mr
Mr = 32.0
your gas has Ar of 16 so your gas is Oxygen
(no idea what you mean by 1gm of the gas)
2.calculate the no. of electrons present in 1.4gms of notrogen gas. 3. How many atoms and molecules of phosphorus r present in 124gms of phosphorus (P4)? 4.... show more
2 answers · Chemistry
Best Answer
1. There is 72g (6*12) of carbon in one mole hence 36g is carbon
2. one mole of electrons has 6.022*10^23 electrons
multiply by 14 since N2 has 14 electrons: 8.43*10^24 electrons per mole N2
there are 0.05 moles of N2 =
4.22*10^23 molecules of electrons
3. 124/ 31 = 4 phosphorous atoms in 124g, this means there are 2.41*10^24 atoms
4. pV=mRT/Mr => 202650*350*10^-6 = 1*8.31*273/Mr
=> 70.9 = 2268.63/Mr
Mr = 32.0
your gas has Ar of 16 so your gas is Oxygen
(no idea what you mean by 1gm of the gas)
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