Chemistry, asked by zs13641228, 7 months ago

The mass of chloride ions present in 5.2g of barium chloride is approximately. [Ba = 137].

Answers

Answered by seemajadhav

1

Explanation:

BaCl2=137+2×35.5

=208

moles of BaCl2=5.2÷208

0.025

1 BaCl2 contain 2 atoms of Cl

hence,

2×0.025

=0.5g

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