Question

The mass of chlorine produced when 1 ampher current is passed through NaCl solution for 30 minute is

Answer 1

1*30*60/96500 = 0.0186
0.0186*35.5 = 0.662g

Answer 2

Answer: 0.071 g

Explanation:

$Q=I\times t$

where

Q= quantity of electricity in coloumbs

I = current in amperes = 1 A

t= time in seconds =$30\times 60=1800s$

$Q=1A\times 1800s=1800C$

$NaCl\rightarrow Na^++Cl^-$

$2Cl^{-}\rightarrow Cl_2+2e^{-1}$

$96500\times 2=193000Coloumb$ of electricity deposits 1 mole of  $Cl_2$

1800 C of electricity deposits =$\frac{1}{193000}\times 1800=0.009mole$ of $Cl_2$

$Mass={\text {no of moles}}\times {\text {Molar mass}}=0.009\times 71=0.662g$

Thus mass of chlorine deposited is 0.662 g.