the mass of CO2 obtained when 2g of impure limestone is calcined is
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Answered by
16
You use the relative atomic mass of the atoms.
Carbon has a relative atomic atomic mass of 12. Oxygen has a relative atomic mass of 16, so two of them is 32.
Hence in whichever mass CO₂ you choose, there will be (12 ÷ (12 + 32)) × 100% = 27.3% to 3sf.
Carbon has a relative atomic atomic mass of 12. Oxygen has a relative atomic mass of 16, so two of them is 32.
Hence in whichever mass CO₂ you choose, there will be (12 ÷ (12 + 32)) × 100% = 27.3% to 3sf.
Answered by
63
CaCO3------->CaO+CO2
So we can say,
100g of CaCO3 is equivalent to 44g of CO2.
1g of CaCO3 is equivalent to 44g/100of CO2.
2 of CaCO3 is equivalent to 44/100g*2 of CO2
=0.88 g
So we can say,
100g of CaCO3 is equivalent to 44g of CO2.
1g of CaCO3 is equivalent to 44g/100of CO2.
2 of CaCO3 is equivalent to 44/100g*2 of CO2
=0.88 g
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