Question

the mass of co2 that must be mixed with 20 g of oxygen such that 27 ml of a sample of the resulting mixture would contain equal number of molecules of. each gas​

Answer 1

Answer:

27.5 grams

Explanation:

C+O

2

→CO

2

Molecular weight of O

2

=32

Number of moles of oxygen in 20 g oxygen =

32

20

=0.625

For equal number of molecules of O

2

& CO

2

, the number of moles of O

2

& CO

2

should be equal.

Hence, number of moles of CO

2

=0.625

So, mass of CO

2

required =0.625×44=27.5g.