Question

The mass of cu that will be deposited at cathode in electrolysis of 0.2M soln of cuso4 when a quantity of electricity equal to that required to liberate 2.24l of h2 at stp from 0.1M aq h2so4

Answer 1

2.24 L of H2 at stp = 0.2gm of H2.

wt of Cu / wt of H2 = Eq mass of Cu / Eq mass of H

i.e.

wt. of Cu/ 0.2 = 63.5/2 / 1

wt. of Cu = 6.35