the mass of cyclist together with the bike is 90 kg. calculate the increase in kinetic energy if the speed increases from 6.0km/h to 12 km/h. ans (375 j)? plzz fast
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mass of bike=90kg
final velocity=12km/h
initial velocity=6.0km/h
Change 6km/h to m/s =6*1000/60*60=5/3Change 12km/h to m/s=12*1000/60*60=10/3Now increase in k.E =1/2 mv²-1/2mu²=1/2m(v²-u²)=1/2*90(75/9)=1/2*750=375 Joule answer
final velocity=12km/h
initial velocity=6.0km/h
Change 6km/h to m/s =6*1000/60*60=5/3Change 12km/h to m/s=12*1000/60*60=10/3Now increase in k.E =1/2 mv²-1/2mu²=1/2m(v²-u²)=1/2*90(75/9)=1/2*750=375 Joule answer
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