the mass of cyclists together and a bike is 90 kg. calculate the increase in kinetic energy if the speed increases from 6km/hr to 12km/hr
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u = 6 km/h = 6 × 5/18 = 5/3 m/s
v = 12 km/h = 12 × 5/18 = 10/3 m/s
Change in KE = 1/2 m(v^2-u^2) = 1/2 × 90 × {(10/3)^2 - (5/3)^2} = 45×(50/9) = 250J
v = 12 km/h = 12 × 5/18 = 10/3 m/s
Change in KE = 1/2 m(v^2-u^2) = 1/2 × 90 × {(10/3)^2 - (5/3)^2} = 45×(50/9) = 250J
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