The mass of Earth is 5.972×10^24kg and its orbital radius is 1.496×10^11m. Calculate its linear momentum
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mass of the earth
= 5.972×10^24kg
Radius of the earth
= 1.496×10^11m
Total distance covered will be equal to the circumference of the circle
D = 2π R
D = 2×3 .14 ×1.496×10^11
D =9.35 × 10^11
time taken in order to complete one revolution
T = 1 year =365 days
T =365 × 24 × 3600
T = 8760×3600
T=3.15 × 10^ 7 sec
Speed
= Distance/ time
= 9.35 × 10^11 /3.15 × 10^ 7
=2.96 × 10^4 m / s
Linear momentum
= m v
= 5.972×10^24× 2.96 × 10^4
=17.6 × 10^28 kg m / s
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