Question

the mass of Earth is 6×10²⁴kg. what is the value of acceleration due to gravity of an object which is at a distance of 19200 km from centre of Earth (G=6.67×10^-11 Nm²/kg²)​

Answer 1

$Mass of earth m_{1} = 6 * 10^{24} kg$

Mass of the object  $m_{2} = 1kg$

Radius of the earth = $6.4 * 10^{6} m$

Universal gravitational constant G = $6.67 * 10^{-11} Nm^{2} kg^{-2}$

By applying universal law of gravitation: - F =  $(\frac{G m_{1} * m_{2} }{r^{2} } )$

 

$=\frac{(6.67 * 10^{-11} * 6 * 10^{24} *1)}{(6.4 * 10^{6})^{2} }$

F = 9.8 N

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