Question

The mass of earth is 6x1024 kg and that of the moon is 7.4x 1022kg. If the distance between the earth and the moon is 3.84x105km. Calculate the force exerted by the earth and the moon.G=6.67x10-11 Nm2 kg-2

Answer 1

Given:-

$M= 6*10^{24} kg$

$m= 7.4*10^{22}kg$

$r=3.84*10^5 km$

$G=6.6743*10^{-11}$

What to find:-

$F_{gravity}$

Procedure:-

We know that

$F_g_r_a_v_i_t_y= \frac{GMm}{r^{2} }$

Plugging all the values, we get

$F_g_r_a_v_i_t_y= 20.1*10^{25} N$

Answer 2

$\huge \sf {\fbox{\fbox{\red{\fbox{Answer:}}}}}$

$\huge \bf{Given:-}$

$\sf {→Mass \: of \: the \: earth,m_1 = 6 \times{{10}^{24} }}$

$\sf {→Mass \: of \: the \: moon,m_2 = 7.4\times{{10}^{22} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{5} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = (3.84\times{{10}^{5} \times 1000)m }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{8}m}}$

$\huge \bf{To \: find:- }$

$\sf{⇒Force \: exerted \: to \: one \: body \: to \: another \: body.}$

$\huge \bf{Formula \: used: - }$

$\leadsto\sf{F =G \times \frac{m_1 \times m_2}{r^2} }$

$\huge \bf{Concept \: used: - }$

$\sf{Gravitational \: constant,G=6.7 \times {10}^{- 11N} N{m}^{2}k {g}^{ - 2} }$

$\huge\bf{According \: to \: Question:-}$

$\bf{F = \frac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22}} {(3.84 \times {10}^{8} )^{2} } = 2.01 \times {10}^{20} newtons}$

$\sf\longmapsto{2.01 \times {10}^{20} newtons}$

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