the mass of ethane required to produce 17.6 gram of CO2
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Reaction for the combustion of the Ethane is ⇒
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2C₂H₆ + 7O₂ ----------→ 4CO₂ + 6H₂O
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From this reaction,
∵ 4 mole of the Carbon dioxide is prepared by the 2 mole of the Ethane.
∴ 1 mole of the Carbon dioxide is prepared by the 0.5 mole of the Ethane.
∵ 1 mole of the Carbon dioxide = 44 g.
∴ Moles of the Ethane required for the combustion is 0.5 moles.
Hope it helps
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