Question

The mass of few iron nails was found to be 85 g. When the iron nails were put into a measuring cylinder containing water, the level of water rose from A to B as shown in the diagram. What is the density of iron?

Answer 1

Answer:

The density = $\frac{mass}{volume}$

We're provided with the mass of the nails, i.e., 85g. Now the volume of the nails will be the change in the volume of the water.

(you didn't attached the diagram in the question. Anyways.)

so the density of iron = $\frac{85}{B-A}$ $g /cm^{3}$  

(most commonly, the measuring cylinders have reading in ml so thats why i kept the unit $g /cm^{3}$. )

To convert it into the SI system of units, multiply the density in $g /cm^{3}$ by 1,000.

So the density of iron in SI System = $\frac{85}{B-A}$ × $10^{3}$ $kg / m^{3}$.

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