Question

The mass of flywheel of a steam engine is 3250 kg with the radius of gyration of 1 m. The starting torque of the engine is 4500 n-m. What is the angular acceleration (rad/s2) of the flywheel?

Answer 1

application of Newton's second law of motion in rotational motion

Answer 2

Given :

Mass of flywheel , m = 3250 kg .

Radius of gyration , r = 1 m .

Torque in engine , $\tau=4500\ N-m$ .

To Find :

The angular acceleration $(rad/s^2)$ of the flywheel .

Solution :

We know , torque is given by :

$\tau=mr^2\alpha\\\\\alpha=\dfrac{\tau}{mr^2}$

Putting all given value in above equation , we get :

$\alpha=\dfrac{4500}{3250\times 1^2}\\\\\alpha=1.38\ rad/s^2$

Therefore , angular acceleration of the flywheel is $1.38\ rad/s^2$ .

Learn More :

Rotational Motion

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