Chemistry, asked by prarthanajag, 2 months ago

The mass of glucose that must be dissolved in 50 g of water in order to produce the same lowering of
vapour pressure as is produced by dissolving 1 g of urea in the same quantity of water is
(A) 1g
(B) 3 g
(C) 6 g
(D) 18 g​

Answers

Answered by gurmeetkaur9074gmail
0

Answer:

the answer is 1g

Explanation:

The mass of glucose that should be dissolved in 50 g of water in order to produce the same lowering of vapour pressure as produced by dissolving 1 g of urea in the same quantity of water is.

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