Question

the mass of H2SO4 in 1200ml of its solution of 0.2 N concentration will be:-

Answer 1

volume = 1200ml
mass = m = ?
number of hydrogen ions = n = 2
equivalent mass = molar mass of solute/n
E.M = 2+32+64/2
E.M = 98/2
E.M = 49 g

Normality = mass of solute × 1000 /equivalent mass of solute × volume (in ml)
N = m × 1000/E.M × 1200ml
m = N×E.M×1200/1000
m = 0.2×49×1200/1000
m = 9.8×1.2
m = 11.76 g .

Answer 2

Answer:

The mass of H₂SO₄ in the solution is equal to 11.76grams.

Explanation:

Volume of the solution $V=1200ml$

Molar mass of $H_{2}SO_{4}=98gmol^{-1}$

n-factor of $H_{2}SO_{4}$ = no. of H⁺ ions $=2$

Equivalent mass of $H_{2}SO_{4}$ $=\frac{Molar Mass}{n-factor}$

                                            $=\frac{98}{2}=49geq^{-1}$

So, Normality of the solution $N=\frac{(mass)(1000)}{(Eq. Mass)(Volume)}$

⇒     $0.2=\frac{(m)(1000)}{(49)(1200)}$

⇒     $m=\frac{(0.2)(49)(1200)}{1000}$

∴      $m=11.76g$

Therefore mass of given solute $=11.76g$