Question

the mass of iron piece in 120 g when it is immersed into measuring 50 ml to 80 ml find volume of iron piece​

Answer 1

Explanation:

Solution:

(i) volume of lead piece = V=v_2-v_1V=v

2

−v

1

v_{1\ }=\ 20\ ml\ ,\ v_2\ =\ 30\ mlv

1

= 20 ml , v

2

= 30 ml

= 30 - 20 ml = 10 ml

(ii) density of lead piece = d=\frac{M}{V}d=

V

M

= \frac{115}{10}

10

115

= 11.5\ kg\ cm^{-3}11.5 kg cm

−3