Question

The mass of Jupiter is 1.91 into 10 to power 36 and its diameter is 13.1 into 10 to the power 7 M calculate the escape velocity on the surface of Jupiter

Answer 1

The escape velocity on the surface of Jupiter is 1.97 × 10⁹ m/sec

Given -

• Mass of the Jupiter = 1.91 × 10³⁶ kg
• Diameter of Jupiter = 13.1 × 10⁷ m

We know that escape velocity is

Ve = $\sqrt{2gR}$

where g is acceleration due to gravity and R is radius.

We know that-

g = Gm/R²

By substituting the value we get

Ve = $\sqrt{\frac{2GM}{R} }$

Ve = ( 2× 6.67 × 10⁻¹¹ × 1.91 × 10³⁶ / 6.55 × 10⁷) ^ 1/2

Ve = 1.97 × 10⁹ m/sec