Question

the mass of Jupiter is 2×10^27 and its radius is 7×10^7 m. at what height from the surface of the Jupiter acceleration due to gravity of Jupiter equal to that on earth surface(ge=9.8)​

Answer 1

Explanation:

We know that,

g=R2GM

Here, M=2×1027kg

R=7.14×107m

∴g=(6.67×10−11)((7.14×107)22×1027)

∴g=26.17m/s2