The mass of Jupiter is 319 times greater than Earth and it's radius is 11 times greater than Earth. If the acceleration due to gravity on the Earth surface is 9.8 m/sec square, calculate the acceleration due to gravity on the surface of Jupiter.
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Given that,
Mass of the earth =M
Radius of the earth = R
We know that,
g=
R
2
GM
Now, mass and radius is double
g
′
=
4R
2
G2M
g
′
=
2R
2
GM
g
′
=
2
1
g
Hence, the acceleration due to gravity on the surface of a planet is
2
1
g
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