The mass of lead piece is 400g. when it is immersed into a measuring cylinder, the water level [2] rises from 30ml to 50ml mark. find 1) volume of lead piece 2) density of metal piece in
g/cm^3
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Explanation:
volume of lead piece = V=v_2-v_1
v_{1\ }=\ 20\ ml\ ,\ v_2\ =\ 30\ ml
= 30 - 20 ml = 10 ml
(ii) density of lead piece = d=\frac{M}{V}
= \frac{115}{10}
= 11.5\ kg\ cm^{-3}
Answered by
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Answer:
hlo your question is wrong
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