the mass of mars is 6.39× 10 √ 23 kg and that of the Jupiter is 1.89×10√27 kg. the distance between Mars and Jupiter is 749 ×10√3 m. calculate the force exerted by the Jupiter kn the mass where
G = 6.7×10√-11 NM√2 /kg√2
Answers
Answer:
F = 1.475683442x10^27
Explanation:
Use Newton's law of universal gravitation formula:
F = (GMm)/r^2
where:
F = gravitational force (in Newtons)
M is the mass of object 1 (in kg)
m is the mass of object 2 (in kg)
r is the distance between the CENTRES of objects 1 and 2 (in metres)
G is the gravitational constant (6.7 x 10^-11 N m^2 kg^-2)
Working out:
You have given the masses of Jupiter as (1.89 x 10^27) kg and Mars (6.39 x 10^23) kg, and the distance between the two as (749 x 10^3) metres so I will use these values.
Assuming you did not include the radius of the two planets in your given distance, I will include them.
Jupiter has radius 69911000 metres, and Mars has radius 3389500 metres. Add the two radii to the distance between the two planets.
(3389500) + (69911000) + (749 x 10^3) = 74049500 metres = r (distance between the CENTRES of objects 1 and 2 in metres)
Sub values into equation listed above:
M = (1.89 x 10^27) kg, m = (6.39 x 10^23) kg, r^2 = (74049500)^2
G is a constant = (6.7 x 10^-11)
F = [ (6.7 x 10^-11) x (1.89 x 10^27) x (6.39 x 10^23) ] / (74049500)^2
= 1.475683442x10^27