Question

The mass of mg3n2 produced if 48 gram of mg is reacted wit 34g of nh3 gas is
3Mg+2Nh3 gives Mg3N2 + 3h2

Answer 1

Mg = 24

Mg3N2 = 24x3 + 14x2 = 100g/mol


NH3 = 14 + 1x3 = 17g/mol



Moles of Mg = 48/24 = 2


Moles of NH3 = 34/17 = 2



From the equation, 


3Mg+2NH3 = Mg3N2 + 3H2


2 moles of NH3 react with 3 moles of Mg


Implies that NH3 is the limiting reagent and that 1 mole of Mg3N2 will be produced



Mass of Mg3N2 produced = Molar mass x number of moles


= 100 x 1

= 100g