The mass of moon is 80 times lesser than the mass of earth. Its radius if 4 times lesser than
earth. Find acceleration due to gravity on its surface. Given that on the surface of earth,
acceleration due to gravity is 9.8 ms-2. State the properties of core of the earth?
Answers
Answer:
Solution :-
g=
g= R
g= R 2
g= R 2
g= R 2 GM
g= R 2 GM
g= R 2 GM
g= R 2 GM 9.8=
g= R 2 GM 9.8= R
g= R 2 GM 9.8= R 2
g= R 2 GM 9.8= R 2
g= R 2 GM 9.8= R 2 GM
g= R 2 GM 9.8= R 2 GM
g= R 2 GM 9.8= R 2 GM
g= R 2 GM 9.8= R 2 GM g
g= R 2 GM 9.8= R 2 GM g ′
g= R 2 GM 9.8= R 2 GM g ′ =
g= R 2 GM 9.8= R 2 GM g ′ = 80×R
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 =
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM ×
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 20
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201 =
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201 = 20
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201 = 209.8
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201 = 209.8
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201 = 209.8
g= R 2 GM 9.8= R 2 GM g ′ = 80×R 2 GM×4 = R 2 GM × 201 = 209.8 g =0.49 ms-²