The mass of N2F4 produced by the reaction of of 2.0 gram of NH3 and 8.0 gram of f2 is is 3.56 gram. what is the percentage yield ?
Answers
Answered by
0
Answer:
2NH3(g)
+
190g
5F
2
→
104g
N
2
F
4
+6HF
Amount of N
2
F
4
formed by 2g NH
3
=
34
104
×2=6.12
Amount of N
2
F
4
formed by 8g F
2
=
190
104
×8=4.38
N
2
F
4
will be limiting and actual amount of product is 3.56 g
∴ % yield =
Calculatedamountofproduct
Actualamountofproduct
×100
=
4.38
3.56
×100=81.28%
Similar questions