Question

The mass of N2F4 produced by the reaction of of 2.0 gram of NH3 and 8.0 gram of f2 is is 3.56 gram. what is the percentage yield ?​

Answer 1

Answer:

2NH3(g)

+

190g

5F

2

→

104g

N

2

F

4

+6HF

Amount of N

2

F

4

formed by 2g NH

3

=

34

104

×2=6.12

Amount of N

2

F

4

formed by 8g F

2

=

190

104

×8=4.38

N

2

F

4

will be limiting and actual amount of product is 3.56 g

∴ % yield =

Calculatedamountofproduct

Actualamountofproduct

×100

=

4.38

3.56

×100=81.28%