Question

the mass of Na2co3 required to prepare 500ml of 0.1M solution
​

Answer 1

Answer:

Weight of Na

2

CO

3

=

1000

Molarity×Mo1.wt.×V

(where V is in ml).

Substituting values in the above equation, we get-

Weight of Na

2

CO

3

=

1000

0.1×106×500

=5.3 g.

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Answer 2

Answer:

The mass of Na2Co3 is 5.3gm

Explanation:

Given that,

The volume of solution=500ml

The molarity of Solution=0.1M

The solute is Sodium Carbonate(Na2Co3) hence,its molecular weight is

$2\times46+12+3\times16 = 106g/mol$

Since,molecular weight is known,no.of moles can be found as follows

$n = \frac{wt.of \: solute}{mol.wt \: of \: solute}$

Let the weight of solute be 'x'gm.Therefore,

$n = \frac{x}{106}$

The formula of molarity is given as follows

$molarity = \frac{n}{volume(in \: ml)} \times 1000$

Now substituting the known values,we get

$0.1 = \frac{ \frac{x}{106} }{500} \times 1000 = = > x = 5.3gm$

Therefore,the mass of Na2Co3 is 5.3gm

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