The mass % of NAOH is 5 molal aqueous Naoh solution is ( atomic weight of Na = 23) 1} 18% 2} 20% 3}16.7% 4)18.6%
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Given:
The molality of NaOH solution, m = 5 m
To Find:
The mass percent of NaOH in the solution.
Calculation:
- 5 molal aqueous solution of NaOH means 5 moles of NaOH are dissolved in 1 kg water.
- So, the mass of 5 moles of NaOH, w = 5 × 40 = 200 gm
- The total mass of solution, W = mass of water + mass of NaOH
⇒ W = 1000 + 200 = 1200 gm
- Mass percent = (w/W) × 100
⇒ Mass percent = (200/1200) × 100
⇒ Mass percent = 16.7 %
- S0, the correct answer is option (3) 16.7 %.
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Explanation:
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