Question

The mass of NH3 containing 9 g of `H' atoms is

Answer 1

Molar  mass of the Ammonia = 14 + 1 × 3 = 17 g.

Now, Mass of the Hydrogen in ammonia = 1 × 3 = 3 g.

This means that,

3 g of the Hydrogen is present in the 17 g of the Ammonia (1 mole)

∴ 1 g of the Hydrogen is present in the 17/3 g of the Ammonia.

⇒ 9 g of the Hydrogen is present in the 17 × 3 g = 54 g of the Ammonia.

∴ Mass of the Ammonia or NH₃ Containing 9 g Hydrogen is 54 g.

Hope it helps.

Answer 2

Molar  mass of the Ammonia = 14 + 1 × 3 = 17 g.

Now, Mass of the Hydrogen in ammonia = 1 × 3 = 3 g.

This means that,

3 g of the Hydrogen is present in the 17 g of the Ammonia (1 mole)

∴ 1 g of the Hydrogen is present in the 17/3 g of the Ammonia.

⇒ 9 g of the Hydrogen is present in the 17 × 3 g = 54 g of the Ammonia.

∴ Mass of the Ammonia or NH₃ Containing 9 g Hydrogen is 54 g.