the mass of Nitrogen in 1 kg of Ammonium Nitrate is
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fist calculate moles of ammonium nitrate present
n=wt of ammonium nitrate/molar mass
n=1000/80
n=12.5
since 1 mole of NH4NO3 contains 1 mole of N2
therefore 12.5 moles of ammonium nitrate will contain 12.5 moles of nitrogen
moles of nitrogen=wt. of nitrogen/molar mass of nitrogen
12.5=wt/28
hence wt=12.5×28
wt=350g
hope this helps u
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