The mass of oxalic acid crystals(h2c2o4.2h2o)required to prepare 50ml of a 0.2n solution is
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Answered by
22
Answer:
0.63 g is the mass of oxalic acid crystals required to prepare 50 ml of a 0.2 N solution.
Explanation: -
Oxalic acid exists as the dihydrate C₂H₂O₄.2H₂O.
Molecular weight of oxalic acid dihydrate = 126 g / mol.
Gram equivalent weight = Molecular weight / basicity
= = 63 g / mol
1 Normal solution of oxalic acid should have 63 g in 1 L.
0.2 Normal solution of oxalic acid should have
= 12.6 g in 1 L.
0.2 Normal solution of oxalic acid should have in 50 mL.
= 0.63 g in 50 mL.
Answered by
7
Explanation:
Solution is Molecular weight of oxalic acid dihydrate = 126 g / mol.
so by the according to the question,
Normal solution of oxalic acid should have 63 g in 1 L. 0.2 Normal solution of oxalic acid should have in 50 mL..
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