Question

The mass of oxalic acid crystals required to prepare 50 ml of a 0.2n solution is

Answer 1

Answer: -

0.63 g is the mass of oxalic acid crystals required to prepare 50 ml of a 0.2 N solution.

Explanation: -

Oxalic acid exists as the dihydrate C₂H₂O₄.2H₂O.

Molecular weight of oxalic acid dihydrate = 126 g / mol.

Gram equivalent weight = Molecular weight / basicity

= $\frac{126g}{2}$ = 63 g / mol

1 Normal solution of oxalic acid should have 63 g in 1 L.

0.2 Normal solution of oxalic acid should have $\frac{63 g }{1} x 0.2$

= 12.6 g in 1 L.

0.2 Normal solution of oxalic acid should have $\frac{12.6 g}{1000}x 50$ in 50 mL.

= 0.63 g in 50 mL.

Answer 2

Explanation

Answer: -

0.63 g is the mass of oxalic acid crystals required to prepare 50 ml of a 0.2 N solution.

Explanation: -

Oxalic acid exists as the dihydrate C₂H₂O₄.2H₂O.

Molecular weight of oxalic acid dihydrate = 126 g / mol.

Gram equivalent weight = Molecular weight / basicity

= \frac{126g}{2}

2

126g

= 63 g / mol

1 Normal solution of oxalic acid should have 63 g in 1 L.

0.2 Normal solution of oxalic acid should have \frac{63 g }{1} x 0.2

1

63g

x0.2

= 12.6 g in 1 L.

0.2 Normal solution of oxalic acid should have \frac{12.6 g}{1000}x 50

1000

12.6g

x50 in 50 mL.

= 0.63 g in 50 mL.