The mass of oxygen having same number of molecules as there in 88 g CO2
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In 1 mole (44g) CO2 thr r 2N no. of oxygen atoms......therefore in 88g thr will be 4N oxygen atoms.
Where N is avogadro number = 6.023*10^23
Similarly,for CO (28g=1 mole),
28g---> N O atoms
x g---> 4N O atoms
Therefore 4*28=112g required
Explanation:
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