The mass of oxygen that is required for the complete combustion of 2.8kg ethylene
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Answer:
Explanation:
1 kg of ethylene will need (0.096/0.028) = 3.42 kg of oxygen. So, 2.8 kg of ethylene will need (3.42 x 2.8) = 9.6 kg of oxygen.
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Hey
Explanation:
1 kg of ethylene will need (0.096/0.028) = 3.42 kg of oxygen. So, 2.8 kg of ethylene will need (3.42 x 2.8) = 9.6 kg of oxygen.
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