Question

the mass of photon of an electromagnetic radiation of wavelength 2209 A° is?​

Answer 1

Answer:

mass of photon of an electromagnetic radiation is = m = 1.009x10^-35 kg

Explanation:

According to De broglie ,

P = h / lambda

where P is momentum .

P = mv

Therefore,

mv = h / lambda

m = h / lambda *v

m = (6.64X10^-34)/(2209x10^-10 * 3x10^8)

m = 1.009x10^-35 kg

Answer 2

Answer:

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