Question

The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit) The binding energy of 2H^4 is (mass of helium nucleus = 4.0015 u)

28. 4 MeV
0.061 u
0.0305 J
0.0305 erg
​

Answer 1

Q]____

=> a) 2He^4

2He^4 contains 2 neutrons and 2 protons

So, mass of 2 protons = 2× 1.0073 =2.0146 u

So, mass of 2 neutrons = 2× 1.0087

=2.0174 u

Total mass of two protons and two neutrons

= (2.0146 + 2.0174 ) u = 4.032 u

Mass of helium nucleus = 4.032 u

Thus, mass defect is lacking of mass in forming the helium nucleus from 2 protons and 2 neutrons.

∴ ∆m = mass defect = (4.032 - 4.0015)u

= 0.0305 u

As we know that, 1u = 931 MeV

Hence, binding energy

∆E = ( ∆m ) × 931

= 0.0305 × 931

= 28.4 MeV

∴ The binding Energy ∆E = 28.4 MeV !

Answer 2

Answer:

♣️The binding energy ∆E is 28.4 MeV..♣️

Explanation:

♥️Hope it will be helpful ☺️ thank you!!♥️