The mass of sodium hydroxide required to prepare 100 mL of 0.05 M aqueous NaOH (Molar
mass = 40 g/mol) solution is
(1) 0.3 g (2) 0.4 g
(3) 0.1 g (4) 0.2 g
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Answer:
(4) 0.2 g
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The required mass of NaOH is 0.2 grams. (Option 4)
Given,
Molarity = 0.05 M
Volume = 100 mL
Molar Mass of NaOH = 40 g/mol
To Find,
Mass of Sodium required to prepare the given solution
Solution,
Molarity is the quantity of solute contained in exactly 1 liter or 1000 milliliters of solution.
The molarity of a solution is,
Molarity =
Let the moles of solute (NaOH) be 'n'
0.05 =
5 = n * 1000
n = 0.005
Mass of NaOH = Moles of NaOH x Molar mass of NaOH
Let the mass of NaOH needed to be 'x'
x = 0.005 * 40
x = 0.2 g
Hence, The required mass of NaOH is 0.2 grams.
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