Chemistry, asked by dhruvi5311, 9 months ago

The mass of sodium hydroxide required to prepare 100 mL of 0.05 M aqueous NaOH (Molar

mass = 40 g/mol) solution is

(1) 0.3 g (2) 0.4 g

(3) 0.1 g (4) 0.2 g​

Answers

Answered by sanjai15102005
0

Answer:

(4) 0.2 g​

Explanation:

Attachments:
Answered by HanitaHImesh
2

The required mass of NaOH is 0.2 grams. (Option 4)

Given,

Molarity = 0.05 M

Volume = 100 mL

Molar Mass of NaOH = 40 g/mol

To Find,

Mass of Sodium required to prepare the given solution

Solution,

Molarity is the quantity of solute contained in exactly 1 liter or 1000 milliliters of solution.

The molarity of a solution is,

Molarity = \frac{Moles of solute * 1000}{Volume of solution in mL}

Let the moles of solute (NaOH) be 'n'

0.05 = \frac{n*1000}{100}

5 = n * 1000

n = 0.005

Mass of NaOH = Moles of NaOH x Molar mass of NaOH

Let the mass of NaOH needed to be 'x'

x = 0.005 * 40

x = 0.2 g

Hence, The required mass of NaOH is 0.2 grams.

#SPJ3

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