Question

the mass of steam at 100degree celcious is to be passed into water of mass 100g at 20fegree Celsius to rise it's temperature by 5fegree Celsius 1)0.4g 2)0.6 g 3)0.8g 4)1g​

Answer 1

Answer:

Calories needed to raise 100g water by 5°C is

m*s*t

=100*1*5=500cal

Explanation:

This heat is obtained from steam at 100°C whose temp will go down to 25°

(which is final temp of water)

So heat lost by steam is

500cal=g*1*75

so

g=500/(1*75)

=100/15

=6.66grams

Not sure that this and is ✓

Answer 2

Explanation:

heat released=heat gained

ML+msdt= msdt

M(540)+M(1)(100-25)=(100)(1)(5)

M(540)+M(75)=500

M(615)=500

M=500÷615

M=0.8g