Question

The mass of the earth is 5.97 × 1024 kg and its mean radius is 6.371 × 106
m.
Calculate the value of g at the surface of the earth

Answer 1

Explanation:

force=mass*acceleration

=5.97*1024kg*9.81m/sec sq

Answer 2

Answer:

g = 9.81 m/s^2

Explanation:

The mass of the earth is 5.97 × 10^24 kg

the mean radius of earth is 6.371 × 10^6

m.

g = GM/R^2

G =universal gravitational constant =

6.674×10^−11 m3⋅kg−1⋅s−2

$g = \frac{6.674 \times {10}^{ -11} \times 5.97 \times {10}^{24}}{ {(6.371 \times {10}^{6}) }^{2} }$

g = (6.674)*(5.97)*10/(6.371 * 6.371)

g = 9.81 m/s^2

value of g at the surface of the earth = 9.81 m/s^2