Question

The mass of the earth is 6 × 10^24 kg and that of the moon is 7.4 × 10^22 kg. If the distance between the earth and the moon is 3.84 × 10^5 km, Calculate the force exerted by the earth on the moon. G = 6.7 × 10^-11 N m² kg^-2​

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Answer 1

Answer:

20.1 x 10¹9 N

Explanation:

Given that,

Given that,Mass of the Earth m 1 =6*10^ 24 kg

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kg

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moon

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²Now, by using Newton's law of gravitation

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²Now, by using Newton's law of gravitation F = (G*m_{1} * m_{2})/(r ^ 2)

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²Now, by using Newton's law of gravitation F = (G*m_{1} * m_{2})/(r ^ 2)F = (6.7 * 10 ^ - 11 * 6 * 10 ^ 21 * 7.4 * 10 ^ 22)/((3.84 * 10 ^ 8) ^ 2)

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²Now, by using Newton's law of gravitation F = (G*m_{1} * m_{2})/(r ^ 2)F = (6.7 * 10 ^ - 11 * 6 * 10 ^ 21 * 7.4 * 10 ^ 22)/((3.84 * 10 ^ 8) ^ 2)F = (297.48 * 10 ^ 35)/(14.8225 * 10 ^ 16)

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²Now, by using Newton's law of gravitation F = (G*m_{1} * m_{2})/(r ^ 2)F = (6.7 * 10 ^ - 11 * 6 * 10 ^ 21 * 7.4 * 10 ^ 22)/((3.84 * 10 ^ 8) ^ 2)F = (297.48 * 10 ^ 35)/(14.8225 * 10 ^ 16)F = 20.069 * 10 ^ 19

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²Now, by using Newton's law of gravitation F = (G*m_{1} * m_{2})/(r ^ 2)F = (6.7 * 10 ^ - 11 * 6 * 10 ^ 21 * 7.4 * 10 ^ 22)/((3.84 * 10 ^ 8) ^ 2)F = (297.48 * 10 ^ 35)/(14.8225 * 10 ^ 16)F = 20.069 * 10 ^ 19F = 20.1 * 10 ^ 19 * N

Given that,Mass of the Earth m 1 =6*10^ 24 kgMass of the Moon m 2 =7.4*10^ 22 kgDistance between the Earth and the Moond=3.84*10^ 5 km=3.84*10^ 8 m Gravitational Constant G = 6.7 x 10-¹¹ Nm²/kg²Now, by using Newton's law of gravitation F = (G*m_{1} * m_{2})/(r ^ 2)F = (6.7 * 10 ^ - 11 * 6 * 10 ^ 21 * 7.4 * 10 ^ 22)/((3.84 * 10 ^ 8) ^ 2)F = (297.48 * 10 ^ 35)/(14.8225 * 10 ^ 16)F = 20.069 * 10 ^ 19F = 20.1 * 10 ^ 19 * NHence, the gravitational force of attraction is 20.1 x 10¹9 N