Question

The Mass of the earth is 6/10^24kg and that of the moom is 7.4/10^22kg.If the distance between earth and the moon is 3.84/10^5 km ,Calculate force excerted by the earth on the Moon​

Answer 1

Explanation:

$\huge\bf{\mid{\overline{\underline{Answer}}\mid}}$

$\huge\bold{GIVEN:-} \\ \\ M_E = 6 \times {10}^{24} \\ \\ M_m = 7.4 \times {10}^{22} \\ \\ Distance (r) = 3.84 \times {10}^{5} \\ \\ \Large\red{Formula:-} \\ \\ \boxed{F = \frac{ G \times M_1 \times m_2}{{r}^{2}}} \\ \\ F = \frac{ G \times M_1 \times m_2}{{r}^{2}} \\ \\ F = \frac{ 6.673 \times {10}^{-11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22} }{{(3.84 \times {10}^{5})}^{2}} \\ \\ F = 24.465 \times {10}^{(-11 + 22 + 24 - 10 )} \\ \\ \huge{\boxed{\boxed{ F = 24.465 \times {10}^{25} N}}}$

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Answer 2

Answer:

20.2 × 10¹⁹ N

Explanation:

Given :

Mass of earth = 6 × 10²⁴ kg

Mass of moon = 7.4 × 10²² kg

Distance between them = 3.84 × 10⁵ km = 3.84  × 10⁸ m

We have value of G = 6.7 × 10⁻¹¹ N m² kg⁻²

We have to find force :

We have :

F = G m₁ m₂ / r²

F = ( 6.7 × 10⁻¹¹ ) ( 6 × 10²⁴ ) ( 7.4 × 10²² ) / (  3.84 × 10⁸ )² N

F = 20.2 × 10¹⁹ N

Hence force exerted by the earth on the moon is 20.2 × 10¹⁹ N.