Question

The mass of the earth is 6×10^24kg and that of the moon is 7.4×10^22kg. If the distance between the earth and the moon is 3.84×10^5km,calculate the force exerted by the earth on the moon.(Take G=6.7×10^–11 Nm^2 kg^2)​

Answer 1

Answer:

Hello Dear.

Here is the answer---

Given Conditions ⇒

Mass of the Earth(m₁) = 6 × 10²⁴ kg.

Mass of the Moon(m₂) = 7.4 × 10²² kg.

Distance between the Earth and the Moon(d) = 3.84 × 10⁵ km.

 = 3.84 × 10⁸ m.

Gravitational Constant(G) = 6.7 × 10⁻¹¹ Nm²/kg².

Using the Newton's law of Gravitation,

 F = G × m₁×  m₂ × /d².

F is the Force of Gravitation between the Earth and the Moon.

Substituting the Given Values in the Formula,

∴ F = (6.7 × 10⁻¹¹ × 6 × 10²⁴ × 7.4 × 10²²) ÷ (3.84 × 10⁸)²

⇒ F = (6.7 × 6 × 7.4 × 10¹⁹) ÷ (14.7456)

⇒ F = 20.1741 × 10¹⁹ N.

⇒ F ≈ 20.2 × 10¹⁹ N.

Thus, the Gravitational Force of Attraction between the Earth and the Sun is 20.2 × 10¹⁹ N.

Hope it helps.

Answer 2

$\huge \sf {\fbox{\fbox{\red{\fbox{Answer:}}}}}$

$\huge \bf{Given:-}$

$\sf {→Mass \: of \: the \: earth,m_1 = 6 \times{{10}^{24} }}$

$\sf {→Mass \: of \: the \: moon,m_2 = 7.4\times{{10}^{22} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{5} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = (3.84\times{{10}^{5} \times 1000)m }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{8}m}}$

$\huge \bf{To \: find:- }$

$\sf{⇒Force \: exerted \: to \: one \: body \: to \: another \: body.}$

$\huge \bf{Formula \: used: - }$

$\leadsto\sf{F =G \times \frac{m_1 \times m_2}{r^2} }$

$\huge \bf{Concept \: used: - }$

$\sf{Gravitational \: constant,G=6.7 \times {10}^{- 11N} N{m}^{2}k {g}^{ - 2} }$

$\huge\bf{According \: to \: Question:-}$

$\bf{F = \frac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22}} {(3.84 \times {10}^{8} )^{2} } = 2.01 \times {10}^{20} newtons}$

$\sf\longmapsto{2.01 \times {10}^{20} newtons}$

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