Question

The mass of the earth is 6×10²⁴ kg and that of the moon is 7.4×10²² kg. If the distance between the earth and the moon is 3.84×10⁵ km, calculate the force exerted by the earth on the moon. (take G = 6.7×0‐¹¹ Nm²kg-²)​

Answer 1

Answer:

F = 20.1×$\sf{10^{19}}$ N

Explanation:

Given:

• Mass of the earth $\sf{(m_1)}$ = 6×10²⁴ kg
• Mass of the moon $\sf{(m_2)}$ = 7.4×10²² kg
• Distance between the earth and moon (r) = 3.84 ×10⁵ km = 3.84×$\sf{10^8}$ m
• Gravitational constant (G) = $\sf{6.7\times\:10^{-11}}$ Nm²/kg²

To find:

• The force exerted by the earth on the moon.

Solution:

We know that,

• ${\boxed{\sf{F=\dfrac{Gm_1m_2}{r^2}}}}$

[put values]

$\implies \sf \: F= \dfrac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22} }{(3.84 \times {10}^{8} )^{2} } \\ \\ \implies \sf \: F \: = \frac{297.48 \times {10}^{35} }{14.82 \times {10}^{16} } \\ \\ \implies \sf \: F\: = 20.06 \times {10}^{19} \\ \\ \implies \sf \: F \: = 20.1 \times {10}^{19}$

Hence, the gravitational force exerted by the earth on the moon is 20.1×$\sf{10^{19}}$ N.

Answer 2

Answer:

ur answer høpe it helps you .

kiran✌️