Physics, asked by Daksh2111, 1 year ago

the mass of the earth is 6 into 10 raise to 24 kg the distance between the Earth and the Sun is 1.5 into 10 raise to 11 m if the gravitational force between two is 3.5 into 10 raise to 22 and what is the mass of the Sun​

Answers

Answered by karthik2737
3

here is your answer ... I considered the value of Universal Gravitation Constant (G) as 6.67×10^-11...

Attachments:
Answered by Anonymous
4

Given:

  • The mass of the Earth is 6 × 10²⁴ kg
  • The distance between the Earth and Sun is 1.5 × 10¹¹ m
  • The Gravitational Force between the two is 3.5 × 10²² N

Answer

:\implies \sf F = \dfrac{G m_1 m_2}{r^2} \\ \\

:\implies \sf 3.5 \times 10^{22} = \dfrac{(6.7 \times 10^{-11}) \times (6 \times 10^{24} )\times m_2}{(1.5 \times 10^{11})^2} \\ \\

:\implies \sf 3.5 \times 10^{22} = \dfrac{6.7 \times 6 \times 10^{13} \times m_2}{1.5^{2} \times 10^{22}} \\ \\

:\implies \sf 3.5 \times 10^{22} = \dfrac{6.7 \times 6 \times m_2}{1.5^{2} \times 10^{9}} \\ \\

:\implies \sf 3.5 \times 10^{31} = \dfrac{6.7 \times 6 \times m_2}{1.5^{2} } \\ \\

:\implies \sf m_{2} = \dfrac{3.5 \times {10}^{31} \times 2.25}{40.2 } \: kg \\ \\

:\implies \sf m_{2} = \dfrac{78.75 \times {10}^{30} }{40.2 } \: kg\\ \\

:\implies \underline{ \boxed{ \sf m_{2} = 1.96 \times {10}^{30} \: kg}} \\  \\

\therefore \underline{\sf The \:mass\: of\: the\: sun\: is \:1.96 \times {10}^{30} \: kg}. \\

Similar questions